Select all record from emp where job not in SALESMAN or CLERK.
select * from emp where job not in ('SALESMAN','CLERK');
Select all record from emp where ename in 'BLAKE','SCOTT','KING'and'FORD'.
select * from emp where ename in('JONES','BLAKE','SCOTT','KING','FORD');
Select all records where ename starts with ‘S’ and its lenth is 6 char.
select * from emp where ename like'S____';
Select all records where ename may be any no of character but it should end with ‘R’.
select * from emp where ename like'%R';
Count MGR and their salary in emp table.
select count(MGR),count(sal) from emp;
In emp table add comm+sal as total sal .
select ename,(sal+nvl(comm,0)) as totalsal from emp;
Select any salary <3000 from emp table.
select * from emp where sal> any(select sal from emp where sal<3000);
Select all salary <3000 from emp table.
select * from emp where sal> all(select sal from emp where sal<3000);
Select all the employee group by deptno and sal in descending order.
select ename,deptno,sal from emp order by deptno,sal desc;
How can I create an empty table emp1 with same structure as emp?
Create table emp1 as select * from emp where 1=2;
How to retrive record where sal between 1000 to 2000?
Select * from emp where sal>=1000 And sal<2000
Select all records where dept no of both emp and dept table matches.
select * from emp where exists(select * from dept where emp.deptno=dept.deptno)
If there are two tables emp1 and emp2, and both have common record. How can I fetch all the recods but common records only once?
(Select * from emp) Union (Select * from emp1)
How to fetch only common records from two tables emp and emp1?
(Select * from emp) Intersect (Select * from emp1)
How can I retrive all records of emp1 those should not present in emp2?
(Select * from emp) Minus (Select * from emp1)
Count the totalsal, deptno wise where more than 2 employees exist.
SELECT deptno, sum(sal) As totalsal
FROM emp
GROUP BY deptno
HAVING COUNT(empno) > 2
select * from emp where job not in ('SALESMAN','CLERK');
Select all record from emp where ename in 'BLAKE','SCOTT','KING'and'FORD'.
select * from emp where ename in('JONES','BLAKE','SCOTT','KING','FORD');
Select all records where ename starts with ‘S’ and its lenth is 6 char.
select * from emp where ename like'S____';
Select all records where ename may be any no of character but it should end with ‘R’.
select * from emp where ename like'%R';
Count MGR and their salary in emp table.
select count(MGR),count(sal) from emp;
In emp table add comm+sal as total sal .
select ename,(sal+nvl(comm,0)) as totalsal from emp;
Select any salary <3000 from emp table.
select * from emp where sal> any(select sal from emp where sal<3000);
Select all salary <3000 from emp table.
select * from emp where sal> all(select sal from emp where sal<3000);
Select all the employee group by deptno and sal in descending order.
select ename,deptno,sal from emp order by deptno,sal desc;
How can I create an empty table emp1 with same structure as emp?
Create table emp1 as select * from emp where 1=2;
How to retrive record where sal between 1000 to 2000?
Select * from emp where sal>=1000 And sal<2000
Select all records where dept no of both emp and dept table matches.
select * from emp where exists(select * from dept where emp.deptno=dept.deptno)
If there are two tables emp1 and emp2, and both have common record. How can I fetch all the recods but common records only once?
(Select * from emp) Union (Select * from emp1)
How to fetch only common records from two tables emp and emp1?
(Select * from emp) Intersect (Select * from emp1)
How can I retrive all records of emp1 those should not present in emp2?
(Select * from emp) Minus (Select * from emp1)
Count the totalsal, deptno wise where more than 2 employees exist.
SELECT deptno, sum(sal) As totalsal
FROM emp
GROUP BY deptno
HAVING COUNT(empno) > 2
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